ITS 6, ITS 6, ITS 6
Edit: One = Three
Two = Three
Nine = Four
Eleven = Six
Twelve = Six
Its letters, and yes, that's an old one
ITS 6, ITS 6, ITS 6
Edit: One = Three
Two = Three
Nine = Four
Eleven = Six
Twelve = Six
Its letters, and yes, that's an old one
Explain your reasoning.
I didn't knew that, good one.
Already did, just quickly posted before anyone could find that one out
Mkay, fine, you win.
I know a retard one that looks like that, but much easier. I'm going to show it, I don't think it is hard.
1=5
2=8
3=49
4=60
5=X
Which number is X?
PS: Since it's not my turn, if you want, I can already give the answer.
This one is awesome and no one is getting it, although you might have heard it before.
You are in a corridor, the corridor is L shaped, at one end of the Corridor, there are 3 Switches, at the other end, there's a room with a lightbulb, one of the switches turns a light on, the other 2 do nothing. You are free to flip whatever switches you want on and off as long as you wish (although the one that gives light must be the only one on for the light to appear at the bulb. The other 2 need to be off), you can then enter the room and guess which switch turns on the light. You can only go in that room once and you need a way to know it for sure, not leaving it to luck.
How can you know which switch flips the light on?
This one is awesome and no one is getting it, although you might have heard it before.
You are in a corridor, the corridor is L shaped, at one end of the Corridor, there are 3 Switches, at the other end, there's a room with a lightbulb, one of the switches turns a light on, the other 2 do nothing. You are free to flip whatever switches you want on and off as long as you wish (although the one that gives light must be the only one on for the light to appear at the bulb. The other 2 need to be off), you can then enter the room and guess which switch turns on the light. You can only go in that room once and you need a way to know it for sure, not leaving it to luck.How can you know which switch flips the light on?
, I already know the answer to this one I think.
You turn on one for like 5 mins, then turn it off and switch on the next. Then go to the room.
If the light is on, its the middle one (the one you left on) if its off touch it. If its hot, its the first one (the one you left on for 5 mins) otherwise its the last one (the one you didn't touch).
I know a retard one that looks like that, but much easier. I'm going to show it, I don't think it is hard.
PS: Since it's not my turn, if you want, I can already give the answer.
DON'T. I am trying to solve it…
NOOOOOOOOOOOOOOOOOOOOOOOOOO
You win :(
I feel bad by doing this, if you want, the answer is this
! Since 1=5, then 5=1, answer=1.
I lol'd, that image was way too appropriate.
I feel bad by doing this, if you want, the answer is this
! Since 1=5, then 5=1, answer=1.
Dammit… I looked :(
Anyway here is mine.
There are 3 boxes. One of them contains a ruby. On them are inscriptions.
Box 1: There is no ruby in me
Box 2: There is no ruby in me
Box 3: The ruby is in box 1Only one inscription is true. Which box contains the ruby?
in box two , box one says the truth
Box 3 can't be, because if it was true, box 2 would be too. If box 1 was truth, then 3 would be a lie, and so would be 2, so the ruby is in box 2.
.
I just realized I can do some poor rhymes with this phrase, it'll be retarded stuff, so ignore it if you can.
! Box 3 can't be, cause if it was true
So would be when referring to box two
3 would be a lie if box 1 was truth
the same works for 2, so ruby is in two
@metteminne:
in box two , box one says the truth
Box 3 can't be, because if it was true, box 2 would be too. If box 1 was truth, then 3 would be a lie, and so would be 2, so the ruby is in box 2.
.
I just realized I can do some poor rhymes with this phrase, it'll be retarded stuff, so ignore it if you can.! Box 3 can't be, cause if it was true
So would be when referring to box two
3 would be a lie if box 1 was truth
the same works for 2, so ruby is in two
As much as that rhyme entertains me…. Mette got it first, so Ikey mette!!
ok here is one i found
You in a square room with an all southern view. A bear walks past the window. What colour is the bear?
good luck
Yellow because the sun is bathing the bear? Derp derp
White, because you're in a pole, I think.
@metteminne:
ok here is one i found
good luck
White… cuz there are only polar bears at North pole?
I tried, derp derp
Two days ago, George had 8 years. Next year he'll have 11 years. How is it possible?
.
Old, but still good, I guess.
I heard that one before, but completely forgot the answer.
He's an animal? His aging process works differently? Like dog years are smaller than human years
Oh, no, wait, that had to do with those quadruple years, right? Shit, forgot the logic.
Two days ago, George had 8 years. Next year he'll have 11 years. How is it possible?
–-
His ninth birthday was yesterday, with yesterday being December 31st? He turns ten THIS year on December 31st, so NEXT year, he'll turn 11 on December 31st?
Simplifying it a bit.
Two days ago was December 30th, 2010. George was 8.
On December 31st, 2010, George turned 9.
On January 1st, 2011, that would be today.
Next year, December 31st, 2012, george turns 11.
I think??
Nah, he is human, and nothing about those years.
.
EDIT: Kitsune got it, your turn.
Probably superduper easy but whatever.
"13 people came into a hotel with 12 rooms and each guest wanted his own room. The bellboy solved this problem.
He asked the thirteenth guest to wait a little with the first guest in room number 1. So in the first room there were two people. The bellboy took the third guest to room number 2, the fourth to number 3, …, and the twelfth guest to room number 11. Then he returned to room number 1 and took the thirteenth guest to room number 12, still vacant.
How can everybody have his own room?"
He killed one of them. :ninja:
EDIT: I think he killed the second, since he wasn't mentioned to be in any room.
No because it could be at night. Though only black bears cross windows from a southern position due to their eating habit of eating southern fish!
No because it could be at night. Though only black bears cross windows from a southern position due to their eating habit of eating southern fish!
WAAAAAAAAAAAAAT!!!??? I'm laughing
Probably superduper easy but whatever.
"13 people came into a hotel with 12 rooms and each guest wanted his own room. The bellboy solved this problem.
He asked the thirteenth guest to wait a little with the first guest in room number 1. So in the first room there were two people. The bellboy took the third guest to room number 2, the fourth to number 3, …, and the twelfth guest to room number 11. Then he returned to room number 1 and took the thirteenth guest to room number 12, still vacant.
How can everybody have his own room?"
Didn't mention the second guest.
M I S D I R E C T I O N
Close enough.
It's simply not possible because the second guest is not accounted for. Which leo pretty much said, so I'll give it to him.
Killing was more interesting… anyway... an easy one because I'm researching other things and don't want to stop the game.
3 persons go beat Marco and Jozu. But there were 2 fathers and 2 sons doing this, with which characters from One Piece is it possible?
Garp, Dragon, and Luffy?
Garp, Dragon and Luffy.
2 fathers. 2 sons
Akumu got it. Your turn.
WB Rogers and Ace beat the shit out marco and Jozu.
im doing it wrong.
That wasn't really a riddle.
Sweet.
Here's a favorite of mine:
What 8 letter word has KST in the middle, in the beginning, and at the end?
Sweet.
Here's a favorite of mine:
What 8 letter word has KST in the middle | IN the beginning | AND at the end?
Fixed that for you.
Haha, I'm laughing from that, is it really inkstand?
-_- Nice, Chicken.
But I guess Leo gets it because he actually guessed the word.
Do you want to do, Chicken? I don't want to do it now. But if I have to, just tell me.
Go ahead .
So, here I go.
You are in a bifurcation. There are 3 men there, they know the right way to where you want to go. The first always says the truth, the second always lies, the third sometimes lies and sometimes says the thruth. They know one each other, to know who lies and who says the truth. If you can make only one question of yes or no to only one of them, what would you ask to know the right way?
.
It's old.
About the last question, I have some things I'd like to make clear first:
1. When you said only one question to only one man, does it mean that I can only utter one sentence of question once and make a decision based on the answer, or that I can ask just one question to each guard (thus making it three questions in total if I use them all)?
2. About the one who sometimes says yes, other times says no…let's just call him C. When you say that each man already knows each other, does it mean the other two (let's call them A and B, A for truth-teller and B for the liar) know for sure what C will answer if given a question, or will it be totally random only for C to decide? Or, put in in another way; is it possible that C actually has one default reaction (either truth-teller or liar) only that I don't know which one and yet A & B knows? Because, it'll make a huge difference if I ask a question like, "Would B say that C would say the path on the left leads to my destination" towards A (or actually anyone as long as the letters are adjusted accordingly, considering I don't know which is which in the first place).
You have to chose one of the three to make a question. You can add more than 1 question in your answer, for example "What's your name and age?" But of course, have to be yes or no questions.
.
C is totally random. But he will have only one reaction per question, let's say if you asked the question I just said above to him, he wouldn't answer the first as a liar and the second as a truth-teller.
If your hair was on fire….......................what if your fire was on hair?